/*
* JFLAP - Formal Languages and Automata Package
*
*
* Susan H. Rodger
* Computer Science Department
* Duke University
* August 27, 2009
* Copyright (c) 2002-2009
* All rights reserved.
* JFLAP is open source software. Please see the LICENSE for terms.
*
*/
package pumping.cf;
import pumping.Case;
import pumping.ContextFreePumpingLemma;
import pumping.LemmaMath;
/**
* The context-free pumping lemam for L =
* {anbn : n ≥ 0}.
*
* @author Jinghui Lim & Chris Morgan
*
*/
public class AnBn extends ContextFreePumpingLemma
{
public String getTitle()
{
return "a^n b^n : n >= 0";
}
public String getHTMLTitle()
{
return "anbn : n " + GREATER_OR_EQ + " 0";
}
protected void chooseW()
{
w = pumpString("a", m) + pumpString("b", m);
}
public void setDescription()
{
partitionIsValid = true;
explanation = "Because this is a context-free language, a valid decomposition exists. If m " + GREATER_OR_EQ +
" 2, one could choose v to be \"a\" and y to be \"b\", which will work for all values of " +
"i.";
}
public void chooseI()
{
i = 2;
}
protected void addCases()
{
/*
* v is string of a's and y is string of a's
*/
myAllCases.add(new Case()
{
public boolean isCase(String v, String y)
{
if(v.indexOf("a") > -1 && v.indexOf("b") == -1 &&
y.indexOf("a") > -1 && y.indexOf("b") == -1)
return true;
return false;
}
public String description()
{
return "v is a string of \"a\"s and y is a string of \"a\"s";
}
public int[] getPreset()
{
return new int[]{0, 1, 0, 1};
}
});
/*
* v is string of a's and y is string of a's followed by b's
*/
myAllCases.add(new Case()
{
public boolean isCase(String v, String y)
{
if(v.indexOf("a") > -1 && v.indexOf("b") == -1 &&
y.indexOf("a") > -1 && y.indexOf("b") > -1)
return true;
return false;
}
public String description()
{
return "v is a string of \"a\"s and y is a string of \"a\"s followed by \"b\"s";
}
public int[] getPreset()
{
return new int[]{m - 2, 1, 0, 2};
}
});
/*
* v is string of a's and y is string of b's
*/
myAllCases.add(new Case()
{
public boolean isCase(String v, String y)
{
if(v.indexOf("a") > -1 && v.indexOf("b") == -1 &&
y.indexOf("a") == -1 && y.indexOf("b") > -1)
return true;
return false;
}
public String description()
{
return "v is a string of \"a\"s and y is a string of \"b\"s";
}
public int[] getPreset()
{
return new int[]{1, m - 1, 0, 1};
}
});
/*
* v is string of a's followed by b's and y is string of b's
*/
myAllCases.add(new Case()
{
public boolean isCase(String v, String y)
{
if(v.indexOf("a") > -1 && v.indexOf("b") > -1 &&
y.indexOf("a") == -1 && y.indexOf("b") > -1)
return true;
return false;
}
public String description()
{
return "v is a string of \"a\"s followed by \"b\"s and y is a string of \"b\"s";
}
public int[] getPreset()
{
return new int[]{m - 1, 2, 0, 1};
}
});
/*
* v is a string of b's and y is a string of b's
*/
myAllCases.add(new Case()
{
public boolean isCase(String v, String y)
{
if(v.indexOf("a") == -1 && v.indexOf("b") > -1 &&
y.indexOf("a") == -1 && y.indexOf("b") > -1)
return true;
return false;
}
public String description()
{
return "v is a string of \"b\"s and y is a string of \"b\"s";
}
public int[] getPreset()
{
return new int[]{m, 1, 0, 1};
}
});
/*
* v is an empty string and y is a non-empty string
*/
myAllCases.add(new Case()
{
public boolean isCase(String v, String y)
{
if(v.length() == 0 && y.length() > 0)
return true;
return false;
}
public String description()
{
return "v is an empty string and y is a non-empty string";
}
public int[] getPreset()
{
return new int[]{m, 0, 1, 1};
}
});
/*
* v is a non-empty string and y is an empty string
*/
myAllCases.add(new Case()
{
public boolean isCase(String v, String y)
{
if(v.length() > 0 && y.length() == 0)
return true;
return false;
}
public String description()
{
return "v is a non-empty string and y is an empty string";
}
public int[] getPreset()
{
return new int[]{m, 1, 0, 0};
}
});
}
protected void setRange()
{
myRange = new int[]{4, 11};
}
public void chooseDecomposition()
{
//The last character in a^n and the first in b^n
setDecomposition(new int[] {w.length()/2-1, 1, 0, 1});
}
/**
* Checks if the pumped string is in the language.
*
* @return true
if it is, false
otherwise
*/
public boolean isInLang(String s)
{
int a, b;
char[] list = new char[]{'a','b'};
if (LemmaMath.isMixture(s, list))
return false;
a = LemmaMath.countInstances(s, 'a');
b = LemmaMath.countInstances(s, 'b');
if (a==b)
return true;
return false;
}
}